Solving for Speed of Mass After Spring Compression: .15m

AI Thread Summary
To solve for the speed of the mass after spring compression, the conservation of mechanical energy equation is applied: initial gravitational potential energy equals the sum of final gravitational potential energy, kinetic energy, and spring potential energy. The initial energy is calculated as mg(L + 0.8), while the final energy includes mg(L - 0.15), kinetic energy (1/2 mv^2), and spring potential energy (1/2 kx^2). The equation simplifies to mg(L + 0.8) = mg(L - 0.15) + (1/2)mv^2 + (1/2)kx^2. By substituting known values and solving for v, the speed of the mass at .15m compression can be determined. This approach effectively utilizes the principles of energy conservation in a spring-mass system.
Lorbersf
Messages
3
Reaction score
0
A vertical spring is created by affixing one end of the spring with k=500N/m to the floor. A 2.0kg mass is held .8m above the equlibrium position of the free and of the spring and released from rest. What is the speed of the mass when the spring is compressed .15m?

I need help setting up the equation for conservation of mechanical energy...
Ki+Ui=Kf+Uf >>>>>And then solving.
 
Physics news on Phys.org
Initially we have the gravity potential energy of the block which is mg(L+h) where L is the length of the spring (when it is relaxed) and h is the height of the block from the top of the spring. at the final state, we have the gravity potential energy for the block , kinetic energy for the block and the potential energy for the spring.
 
i need more help than that please
 
mg(L+0.8) = mg(L-0.15)+\frac{1}{2}mv^2+\frac{1}{2}kx^2
 

Thread 'Rolling without slipping on a curved surface'

Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »

Similar threads

Find elastic energy in the compressed spring.
Replies
12
Views
3K
Problem with when to use Force and Energy. What compresses spring/
Replies
3
Views
1K
Question about springs and rotational/translational energy
Replies
4
Views
1K
A block of mass m is dropped onto the top of a vertical spring....
Replies
8
Views
5K
How High Does Cheese Rise on a Released Spring?
Replies
1
Views
1K
Solving for Max Compression: 0.2kg Spring
Replies
12
Views
1K
Kleppner - blocks and a compressed spring
Replies
3
Views
3K
Quadratic equation for maximum compression of a spring
Replies
3
Views
3K
Finding the speed of the block for one and two springs
Replies
5
Views
10K
Find the maximum distance the spring will be compressed?
Replies
2
Views
9K

Hot Threads

Recent Insights

Back
Top