Solving for the Horizontal Component of Velocity in a Jetliner Moving at 390 m/s

Thread starter shawonna23
Start date Sep 11, 2004

AI Thread Summary

To find the horizontal component of a jetliner's velocity moving at 390 m/s with a vertical component of 37.4 m/s, the Pythagorean theorem is applicable. The equation involves calculating the square root of the sum of the squares of the total velocity and the vertical component. The correct approach is to isolate the horizontal component using the formula: horizontal velocity = √(total velocity² - vertical component²). The calculation results in a horizontal component of approximately 392 m/s. This confirms the use of Pythagoras in solving for the horizontal component of velocity.

Sep 11, 2004

shawonna23

Hwk. Problem?

A jetliner is moving at a speed of 390 m/s. The vertical component of the plane's velocity is 37.4 m/s. Determine the magnitude of the horizontal component of the plane's velocity.

What equation would I use to solve this problem?

Physics news on Phys.org

Sep 11, 2004

Tide

Science Advisor

Homework Helper

Pythagoras

Sep 11, 2004

HallsofIvy

Science Advisor

Homework Helper

Yep, Pythagoras!

Sep 11, 2004

shawonna23

Am I on the right track...

Take square root of 390^2 + 37.4^2= 392 m/s

Sep 11, 2004

Tide

Science Advisor

Homework Helper

That looks like Pythagoras to me!

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

View full post »

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

View full post »