Solving for Y: 9/4 - 3.3/2 = -9/4 • Physics Forums

r-soy · 2010-06-06T12:45:48+00:00

Hi all the Q y = 9/4 - 3.3/2 the answer = -9/4 but when i try to solve i don't dounf same the answer 9/4 - 3 . 3/2 9/4 + 9 / 2 18 + 36 / 8 = 22.5 this answer which I found regared

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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Solving for Y: 9/4 - 3.3/2 = -9/4

Thread 'Prove that the integral is equal to ##\pi^2/8##'

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