Solving Forces & Torques: The Weight Problem

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The discussion revolves around calculating the torque produced by the weight of a jet engine suspended under an airplane wing. The original attempts to find torque using the formula Torque = Fl were incorrect due to misunderstanding the geometry involved, particularly the use of cosine versus sine in the calculations. Participants emphasize the importance of identifying the correct lever arm and the perpendicular distance from the axis of rotation to the force's line of action. The confusion stems from misapplying trigonometric functions in the context of the problem. Ultimately, the user is encouraged to reassess the geometry and trig functions to solve the torque problem accurately.
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I can't understand why I can't get this problem right. It's irritating me, so any help would be greatly appreciated.

The Problem: The drawing shows a jet engine suspended beneath the wing of an airplane. The weight W of the engine is 9300 N and acts as shown in the drawing. The rotational axis in the drawing is perpendicular to the plane of the paper. With respect to this axis, find the magnitude of the torque due to the following force: the weight.

Drawing

I know how to find torque using Torque = Fl

Initially my equation consisted of:

Torque = 9300(2.50)cos 32 - But my answer was wrong. So I then thought perhaps I should being using gravity in there since W = mg. In using that my second equation consisted of:

Torque = 91140(2.50)cos 32 - But again my answer was wrong.

What am I missing?? This should not be that difficult that's why I'm getting frustrated that I can't figure out something simple, that I'm not just doing right.
 
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Try dividing by cos32 instead of multiplying. Not promising anything, just saying give it a try.

I seem to remember doing problems like this in the past and that was the answer.
 
You are having problem with geometry, look at the triangle again!
 
BlackMamba said:
I know how to find torque using Torque = Fl

Initially my equation consisted of:

Torque = 9300(2.50)cos 32
Why do you multiply by cos 32 ?
So I then thought perhaps I should being using gravity in there since W = mg.
The weight is given; no need to calculate it.
 
I have no idea why I multiply by cos 32. I was just following an example in the book that was similar. Is it supposed to be sin?
 
BlackMamba said:
I have no idea why I multiply by cos 32. I was just following an example in the book that was similar. Is it supposed to be sin?
You tell me. :smile: What's the definition of torque? What distance is involved?
 
Torque is the magnitude of the force times the lever arm. The lever arm being the distance that is invloved.

So...I still don't know what I'm doing wrong.
 
BlackMamba said:
Torque is the magnitude of the force times the lever arm. The lever arm being the distance that is invloved.

So...I still don't know what I'm doing wrong.
The lever arm is the perpendicular distance from the axis of rotation to the line of action of the force.

As Cyclovenom noted, you are having a geometry/trig problem. (Examine the triangle involved, find the side that represents the lever arm, and determine which trig function you need.)
 
Ok, I'll give it another go. Thank you for your help. It's much appreciated. :)
 
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