Solving Frequencies Problem: Lowest Tone in Close-End Pipe 200Hz

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The discussion centers on identifying which frequencies will not resonate in a closed-end pipe with a fundamental frequency of 200Hz. The formula for the fundamental frequency is f_{1} = v/(4L), and subsequent resonant frequencies are calculated using f_{n} = (2n-1)f_{1}. Given the fundamental frequency, the resonant frequencies can be determined. Participants suggest starting with the textbook section on closed-end pipes for clarity. The key focus is on understanding the relationship between the pipe length and the resonant frequencies.
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The lowest tone to resonate in a close-end pipe of length L is 200Hz. Which is of the following frequencies will not resonate in the pipe?

400Hz
600Hz
1000Hz
1400Hz

Anyone know where I should start on this?
 
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I would start with the section in your text on pipes with closed ends.
 
This is simple, just remember for one end closed.

Fundamental Frequency:

f_{1} = \frac{v}{4l}

The rest of the frequencies will be given by

f_{n} = (2n-1)f_{1} ... n=1,2,3...
 
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