Solving Friction Problems: Boy vs Girl Tug-of-War

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SUMMARY

The discussion focuses on solving a tug-of-war problem involving a 65-kg boy and a 45-kg girl on a frictionless surface, with the girl's acceleration towards the boy being 3.0 m/s². The key to solving this problem lies in applying Newton's third law, which states that for every action, there is an equal and opposite reaction. The force exerted by the boy on the girl is equal in magnitude and opposite in direction to the force exerted by the girl on the boy, allowing for the calculation of the boy's acceleration.

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This discussion is beneficial for physics students, educators, and anyone interested in understanding dynamics and force interactions in frictionless scenarios.

SkiingAlta
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Hi,
I am a bit confused with all this friction stuff... How would I begin to solve this problem and by using what formulas? Thanks.

Suppose a 65-kg boy and a 45-kg girl use a massless rope in a tug-of-war on an icy, resistance-free surface. If the accelleration of the girl toward the boy is 3.0 m/s2, find the magnitude of the acceleration of the boy toward the girl.
 
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This is happening on a resistance free surface. There is no friction.

Also, you at least need to attempt the problem on your own. Your hint though is to think about force balancing, and that you only need one formula.
 
In this problem there is no friction. You can solve this problem by using Newton's third law.
From the given data, find the force acting on the girl by boy. The girl must react with same force on boy.
 

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