Solving Frictional Force on Ladder

AI Thread Summary
To solve for the frictional force on the ladder, the equations of equilibrium for forces and torques must be correctly applied. The normal force at the base of the ladder needs to be calculated first, followed by analyzing the moments to determine the frictional force. The angles and distances involved in the problem are crucial for accurate calculations. Clarification on how to apply the angles and lengths in the equations is sought. Understanding these steps is essential for solving the problem effectively.
Power of One
Messages
23
Reaction score
0

Homework Statement


A ladder 12.0m long weighing 125 N rest against a smooth vertical wall. The bottom of the ladder makes an angel of 67 with the deck. A bucket of paint with a mass of 14kg rests o a rung, 7.00m from the bottom end of the ladder. What is the frictional force exerted on the bottom of the ladder?


Homework Equations


T= F x R x Cos theta

The Attempt at a Solution



Sum of forces x: Nw- fs=0
Sum of forces y= Ng- Fg=0
Sum of torques: Tnw- Tfg=0

Do I have these equations correct? I don't know which angles and lengths get plugged into which? Can someone please help me?
 
Physics news on Phys.org
Hi Power of One! :wink:

First find the normal force.

Then take moments to find the friction force. :smile:
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Force of the Ladder on a Wall Torque
Replies
5
Views
3K
Minimum angle the ladder can make with the floor without slipping
Replies
7
Views
15K
Why Isn't the Sum of Torques Zero in This Ladder Equilibrium Problem?
Replies
8
Views
6K
How Much Friction is Needed to Keep the Ladder in Place?
Replies
2
Views
2K
How do I find the forces acting on a ladder?
Replies
9
Views
5K
A ladder against a wall problem
Replies
5
Views
2K
Solve Moment Question: Find Force at Bottom of Ladder
Replies
1
Views
1K
What is the Force of Friction on a Painter's Ladder?
Replies
2
Views
4K
Moments of a Ladder Propped Up Against A Wall
Replies
23
Views
14K
Ladder with 2 forces of friction and a person climbing (statics)
Replies
5
Views
6K

Hot Threads

Recent Insights

Back
Top