Solving Geodesic Equations with Killing Vectors: Is There a General Solution?

In summary, the solution to a geodesic equation depends on the manifold and connection in use, and the Christoffel symbols can be calculated from the geodesic equations or from the metric tensor.
  • #1
AleksanderPhy
43
0
Hello I am concered about way of solving geodesic equation. Is there a general solution to geodesic equation? How to calculate the Cristoffel symbol at the right side of the equation?
Thanks for helping me out!
 
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  • #2
AleksanderPhy said:
Is there a general solution to geodesic equation?
No, the solution depends on the manifold and connection.

AleksanderPhy said:
How to calculate the Cristoffel symbol at the right side of the equation?
This depends on your connection. Since this is the relativity forum and not the differential geometry forum, I assume that you are working with the Levi-Civita connection from a metric tensor. You can then compute the Christoffel symbols directly from the expression in terms of the metric components and their derivatives, or from the geodesic equations resulting from finding the extrema of the integral
$$
S[\gamma] = \int g_{\mu\nu} \dot x^\mu \dot x^\nu d\tau,
$$
where ##\tau## is an affine curve parameter that will be identified with the proper time in the case of a time-like geodesic and ##x^\mu(\tau)## are the coordinates of the curve ##\gamma## in some coordinate system.
 
  • #3
AleksanderPhy said:
Hello I am concered about way of solving geodesic equation. Is there a general solution to geodesic equation? How to calculate the Cristoffel symbol at the right side of the equation?
Thanks for helping me out!

When you have certain symmetries known in the metric, called Killing vectors, writing the solution of the geodesic equations is a lot easier. It's not a formal definition, but if a coordinate system exists where the metric coefficients are not a function of time, the system has a time-like Killing vector that represents a conserved energy. More generally, if a metric exists where none of the metric coefficients are not a function of one of the coordinates, that coordinate represents a symmetry, and the existence of that symmetry implies that there is a conserved energy-momentum (linear or angular, depending on the nature of the coordinate) which is constant along the geodesic.
 

Related to Solving Geodesic Equations with Killing Vectors: Is There a General Solution?

1. What is the "Solutions geodesic equation"?

The solutions geodesic equation is a mathematical equation used in the field of differential geometry to study the paths followed by particles and objects in curved spaces. It helps to determine the shortest or most efficient path between two points in a curved space.

2. How does the solutions geodesic equation differ from other equations used in physics?

The solutions geodesic equation is unique in that it takes into account the curvature of space, whereas other equations in physics typically assume a flat, Euclidean space. This makes it particularly useful for studying the behavior of objects in the presence of strong gravitational fields.

3. What are some real-world applications of the solutions geodesic equation?

The solutions geodesic equation has many practical applications, including in the fields of astronomy, astrophysics, and navigation. It is used to study the motion of celestial bodies, such as planets and stars, and to calculate the trajectories of spacecraft and satellites. It is also used in the development of GPS systems and other navigation technologies.

4. How is the solutions geodesic equation derived?

The solutions geodesic equation is derived from the principles of general relativity, which describe the curvature of space and the behavior of matter and energy. It is based on the concept of a geodesic, which is the shortest or most efficient path between two points in a curved space.

5. Are there any limitations or assumptions to consider when using the solutions geodesic equation?

Like any mathematical equation, the solutions geodesic equation has its limitations and assumptions. It assumes that the space in which the object is moving is static and does not change over time. It also assumes that the object is not affected by any external forces, such as friction or air resistance. These limitations must be taken into account when applying the equation to real-world scenarios.

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