Solving Geodesic Equations with Killing Vectors: Is There a General Solution?

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SUMMARY

The discussion addresses the complexity of solving geodesic equations, emphasizing that no general solution exists as it is contingent on the specific manifold and connection used. The calculation of Christoffel symbols is highlighted as dependent on the Levi-Civita connection derived from the metric tensor. Utilizing Killing vectors simplifies the solution process, particularly when the metric coefficients are independent of time, indicating conserved quantities along geodesics.

PREREQUISITES
  • Understanding of geodesic equations in differential geometry
  • Familiarity with the Levi-Civita connection
  • Knowledge of metric tensors and their derivatives
  • Concept of Killing vectors and their role in symmetries
NEXT STEPS
  • Study the derivation of Christoffel symbols from metric tensors
  • Explore the properties and applications of Killing vectors in general relativity
  • Investigate specific examples of geodesic equations in various manifolds
  • Learn about conserved quantities in the context of geodesic motion
USEFUL FOR

Researchers and students in theoretical physics, particularly those focused on general relativity and differential geometry, as well as mathematicians interested in the applications of symmetries in geometric contexts.

AleksanderPhy
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Hello I am concered about way of solving geodesic equation. Is there a general solution to geodesic equation? How to calculate the Cristoffel symbol at the right side of the equation?
Thanks for helping me out!
 
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AleksanderPhy said:
Is there a general solution to geodesic equation?
No, the solution depends on the manifold and connection.

AleksanderPhy said:
How to calculate the Cristoffel symbol at the right side of the equation?
This depends on your connection. Since this is the relativity forum and not the differential geometry forum, I assume that you are working with the Levi-Civita connection from a metric tensor. You can then compute the Christoffel symbols directly from the expression in terms of the metric components and their derivatives, or from the geodesic equations resulting from finding the extrema of the integral
$$
S[\gamma] = \int g_{\mu\nu} \dot x^\mu \dot x^\nu d\tau,
$$
where ##\tau## is an affine curve parameter that will be identified with the proper time in the case of a time-like geodesic and ##x^\mu(\tau)## are the coordinates of the curve ##\gamma## in some coordinate system.
 
AleksanderPhy said:
Hello I am concered about way of solving geodesic equation. Is there a general solution to geodesic equation? How to calculate the Cristoffel symbol at the right side of the equation?
Thanks for helping me out!

When you have certain symmetries known in the metric, called Killing vectors, writing the solution of the geodesic equations is a lot easier. It's not a formal definition, but if a coordinate system exists where the metric coefficients are not a function of time, the system has a time-like Killing vector that represents a conserved energy. More generally, if a metric exists where none of the metric coefficients are not a function of one of the coordinates, that coordinate represents a symmetry, and the existence of that symmetry implies that there is a conserved energy-momentum (linear or angular, depending on the nature of the coordinate) which is constant along the geodesic.
 

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