Solving GRE Spheres: Find h0 from h

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The discussion centers on a physics problem involving two spheres of putty with different masses, where one sphere is raised and released, colliding with the other and sticking together. The initial approach used conservation of energy to equate initial and final energy states, leading to an incorrect conclusion about the maximum height after the collision. The correct method involves applying the principle of conservation of momentum due to the inelastic nature of the collision, as kinetic energy is not conserved in such scenarios. The correct final height after the collision is determined to be (1/16)h0, highlighting the importance of using momentum conservation in inelastic collisions.
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"Two small spheres of putty, A and B, of mass M and 3M, respectively, hang from the ceiling on strings of equal length l. Sphere A is drawn aside so that it is raised to a height h0 and then released. Sphere A collides with sphere B; they stick together and swing to a maximum height h equal to "

This is an exercise I am perplexed about as to why I got the wrong answer. I used conservation of energy.

Ei = mgh0

Ef = (m+3m)gh

Ef = Ei

mgh0 = (m+3m)gh

Therefore h = (1/4)m

This answer is wrong. The correct answer is (1/16)h0. Where'd I go wrong? Thanks!
 
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They stick together after collision, that (as well as the fact that they are made of putty) should tell you that collision is inelastic and kinetic energy is not conserved. You have to consider momentum conservation to calculate Ef.
 
Thanks!
 
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