Solving Ideal Gas Problem Homework: Final Pressure of Tank w/ Vapor & Water

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The discussion revolves around calculating the final pressure in a closed tank filled with water and vapor, given an initial pressure of 1 bar and a volume of 80,000 m³. The user initially calculated a final pressure of 0.167 bar but questioned this due to the fixed tank volume. They noted that as the volume increases, the pressure should decrease, leading to confusion about the calculations. The user later suggested that if the volume ratio is considered, the pressure could be 6 bar, seeking clarification on this point. The thread highlights the complexities of applying ideal gas laws in scenarios involving fixed volumes and multiple phases.
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Homework Statement


Calculate the final pressure of the closed tank containing vaper if it is filled with a water.If the water mass is 400,000 kg is injected into the tank, initial tank pressure is 1bar and the volume is 80,000m^3, density of the vapor 1 kg/m^3 at 1 bar, treat the air and water as ideal gases.


Homework Equations





The Attempt at a Solution


Volume before V1=80,000m^3
Volume after V2=480,000m^3
initial pressure = 1 bar

final pressure is going to be 0.167 bar, but the question is asking me that with the same tank how much the pressure is going to be and in this case my answer is wrong!

as the volume increase it is normal that the pressure will decrease but if we have a fixed tank!

I really confused!
 
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I think something ring in my head!

Since the initial volume is before V1=80,000m^3
Volume after V2=480,000m^3

if we take the ratio of it V2/V1= 6 in this case the pressure for the same tank is going to be 6 bar! is it true
 
I need a help please
 
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