Solving Impedance/Admittance for V_s w/ 2 Caps, 2 Inductors, 2 Res.

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The discussion focuses on solving for the source voltage V_s in a circuit containing two capacitors, two inductors, and two resistors, given a specific current I_0. The user attempts to combine the equivalent impedance of the left side of the circuit and calculates intermediate voltages and currents using KCL and KVL. They derive V_o and I_L, and then express I_1 in terms of these values. The user seeks confirmation on their final calculation of V_s, which they have found to be approximately 9.581 cos(t + 29.70). The thread emphasizes the importance of correctly applying circuit analysis techniques to arrive at the solution.
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Impedance and Admittance: Find Vs given Io in a circuit with 2 caps,2 inductors,2res

Homework Statement



Find V_s if I_0\,=\,2\angle0\deg A.

http://img237.imageshack.us/img237/6291/problem954zz0.jpg

Homework Equations



KCL, KVL

The Attempt at a Solution



I made a new diagram:

http://img201.imageshack.us/img201/9359/problem954part2gz3.jpg

But how do I combine the left hand equivalent impedance, so that the final circuit to work on would be this:

http://img201.imageshack.us/img201/1690/problem954part3fj1.jpg \frac{1}{Z_3}\,=\,\frac{1}{Z_1}\,+\,\frac{1}{j4\Omega}\,=\,\frac{1}{2\,+\,2j}\,+\,\frac{1}{4j}

Figuring V_o:

V_o\,=\,I_o\,Z_2\,=\,\left(2\angle0\right)\left(2\angle45\right)\,=\,4\angle45

I_L\,=\,\frac{V_0}{j2}\,=\,\frac{4\angle45}{\sqrt{2}\angle63.43}\,=\,\frac{4}{\sqrt{2}}\angle-18.43

I_1\,=\,-\left(I_L\,+\,I_0\right)\,=-\left[\,\left(\frac{4}{\sqrt{2}}\angle-18.43\right)\,+\,\left(2\angle0\right)\right]

V_1\,=\,I_1\,Z_1

I need this to find V_s.

V_s\,=\,V_1\,-\,V_0

How do I finish? Please help!
 
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I did the calculations and conversions of complex rectangular to polar and got this as a final answer:

V_S\,=\,9.581\,cos\left(t\,+\,29.70)

Does that look right?
 
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