Solving Improper Integrals: $\int_2^{inf} \frac{2}{(x+3)^{3/2}}$

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The discussion centers on evaluating the improper integral $\int_2^{\infty} \frac{2}{(x+3)^{3/2}}$. After integrating, the result is expressed as $\frac{-4}{\sqrt{x+3}}$, and the limit as \( b \) approaches infinity is analyzed. Participants clarify that as \( b \) approaches infinity, the function approaches zero, leading to the conclusion that the integral converges to \( \frac{4}{5} \). Miscalculations are acknowledged, and the importance of correctly evaluating limits in improper integrals is emphasized. Ultimately, the integral converges, and the correct answer is confirmed as \( \frac{4}{5} \).
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\int_2^{inf} \frac{2}{(x+3)^{3/2}}

integrating the problem, i get:
\frac{-4}{sqrt(x+3)}

now integrating from 2 to inf(replaced with b), plugging in 2, i get -4/5:
f(b) + 4/5
lim->inf

it looks like f(b), lim->inf goes to -4 X 10^-inf

so wouldn't the answer just be divergent? i also tried 4/5 and -4/5, but it wouldn't work. i don't really know the proper way to find the limit. all i do is plug in the largests number and try to find a pattern.
 
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What is lim_{x \rightarrow \infty}\frac{1}{x^n} where n is any positive real number ?
 
looks like it goes to zero
 
yes, but i still don't get it... what are you trying to tell me?


are you saying that f(b),lim->inf goes to zero? and the answer should be 4/5?
 
ah, thanks for the help. actually, f(2) is not equal to 4/5, i typed it wrong in my calculator. i need some sleep, thanks agian.
 
I realize that i didn't bother to do the calcuation for you and that's why i agreed with you...:wink:

Daniel.
 
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