Solving Impulse-Diffy Equation: y''+2y'+3y=sin(t)+δ(t-3π)

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Homework Statement


y''+2y'+3y=sin(t)+\delta (t-3 \pi )


Homework Equations





The Attempt at a Solution


Left side is just Y(s)*(s^2+1)-1
But I don't know how to deal with the delta function, I made it into just an intergral but I don't know how to intergrate it.
 
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L[\delta(t-t_0)]=e^{-t_0 s}


If I remember correctly that is.
 
thanks=)
 
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