Solving Integral Troubles with Vibrations Problem

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Homework Help Overview

The discussion revolves around evaluating integrals related to a vibrations problem, specifically focusing on the integral involving the cosine function. Participants are exploring methods to simplify the integral and clarify the setup.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply a substitution method to simplify the integral. Some participants question the limits of integration after the substitution. Others suggest using the double angle formula for cosine to avoid substitution altogether.

Discussion Status

Participants are actively engaging with the problem, offering different approaches and clarifying points of confusion. There is a mix of suggestions regarding the use of substitution and trigonometric identities, indicating a productive exploration of the topic.

Contextual Notes

One participant introduces a separate integration problem, questioning the integration of a derivative and the implications for finding a constant. This indicates a broader context of integration challenges within the thread.

Saladsamurai
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Homework Statement



Alrighty. I have reduced a vibrations problem to an integral and I am having some trouble
evaluating it.

I have a value for t and need to find:[tex]-c\omega^2Z^2\int_0^t\cos^2(\omega t-\phi)\ dt[/tex] (1)I guess it is just my memory that is the problem.

If I had [itex]\int\cos^2(x)\ dx[/itex] It would not be a problem.

I am thinking now that I type this that a simple U substitution should do the trick right?EDIT:

If I let [itex]u=\omega t-\phi\ \Rightarrow du=\omega\ dt[/itex]

So (1) becomes:

[tex]-c\omega Z^2\int_0^t\cos^2u\ du[/tex]

Yes?
 
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hi - i think your limits should become u(0) & u(t) as well
 
If you just use the the double angle formula
[tex]\cos^2 t = \frac{1}{2} (1+\cos 2t) [/itex]<br /> from the outset (because it's the next step after your u-substitution anyway), then you really don't need to do a u-substitution if [itex]\omega[/itex] and [itex]\phi[/itex] are just constants.[/tex]
 
pls help me too...integration problem

hi... i am new here and i hope someone can please answer my question too..

x-1 + dk/dy = x-1
so when we cancel both x-1 we get dk/dy = 0

my question is can i integrate dk/dy to get the k's value??

if i integrate dk/dy, am i getting C (constant) for the k value?

thank u very much...
 
Yes, if dk/dy = 0, then k = a constant.
 

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