Solving Iterative Formulas: Xn+1 Explained

DeanBH
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Homework Statement



First of all this is revision not homework =)

question is Xn+1 = Cuberoot ( 17.5-2xn)

answer lies between 2 and 3. i know the answer is 2.34 but what i don't get is why it is
xn+1 = equation, because when you put xn=2.34 into the equation you get 2.34 out.
shouldnt get 3.34 out if its xn+1. what's the purpose of the n+1!
 
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xn and xn+1 both go (in this convergent case) to a limit call it L. Now substitute L for xn and xn+1 and solve the equation.
 
dirk_mec1 said:
xn and xn+1 both go (in this convergent case) to a limit call it L. Now substitute L for xn and xn+1 and solve the equation.

i don't think you understand what I'm confused with,



i know the answer is 2.34 so i put it into check

xN+1 = cuberoot(17.5-2xn)

3.34=cuberoot(17.5-2*2.34)
3.34=2.34

do you understand what i don't understand.
 
You've made an error in your calcution it is correct.
 
If you mean

x_{n+1}=(17.5+2x_n)^{1/3}

then the answer is \lim_{n\to\infty}x_n=2.34, and this solution can be found as dirk_mec1 described.

But if you mean

x_n+1=(17.5+2x_n)^{1/3}

then x_n=1.44 for all n.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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