Solving LCR Circuit: Find C, I_rms, I_rms at Resonance

AI Thread Summary
In a series LCR circuit with R=69.0 Ω and L=0.100 H, driven by a sinusoidal emf of Erms=6.70 V at 250 Hz, the current leads the emf by 54.0 degrees. To find the capacitance C, the equation tan(phi) = (WL - (1/WC))/R should be corrected to tan(phi) = ((1/WC) - WL)/R, reflecting the phase relationships in the circuit. The rms current can be calculated using Irms = IP/sqrt(2) and the impedance Z. The resonant frequency is given by Wo = 1/sqrt(LC), which will affect the rms current when the frequency changes. Clarification on the phase angle is essential for accurate calculations.
tomrja
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Homework Statement



Consider a series LCR circuit with R= 69.0 Ω and L= 0.100 H, driven by a sinusoidal emf with Erms= 6.70 V at frequency f= 250 Hz. The sinusoidal current leads the emf by 54.0 degrees.

a) Calculate the capacitance C.
b) What is the rms current in the circuit?
c) If the frequency of the emf is changed to the resonant frequency of the circuit, what is the rms current?

Homework Equations



tan(phi)=(WL-(1/WC))/R

Ip= Vp/Z = Vp/sqrt(R^2+(XL-XC)^2)

Irms=IP/sqrt(2)

W=2*pi*f

Wo=1/sqrt(LC) resonant frequency

The Attempt at a Solution



I solved tan(phi)=(WL-(1/WC))/R for C and got C=1/(W(WL-Rtan(phi)) then plugged in all given info to solve for C. It says that the answer is wrong and I am assuming that I plugged in the wrong phi. "The sinusoidal current leads the emf by 54.0 degrees." I don't know what this means. I have not started on the other two parts of the problem because I need to find C first. What am I doing wrong? Thanks!
 

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Hi tomrja :smile:
(have a phi: φ)

tomrja said:

tan(phi)=(WL-(1/WC))/R


i didn't read all of your post but the thing i quoted is wrong

tan\phi = \frac{\frac{1}{wC} - wL}{R}

thats because current in capacitor leads voltage by 90 and lags in inductor by 90
 
and for iRMS use

iRMS = ERMS/Z
 
hi tomrja! :smile:
tomrja said:
"The sinusoidal current leads the emf by 54.0 degrees." I don't know what this means.

it means that if V = Vmaxsinωt, then I = Imaxsin(ωt + 54°)

in other words, the impedance is Z = |Z|ei54π/180
 
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