"Solving Light Problem with Wavelength 635 nm

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The problem involves calculating the number of bright fringes formed by light of wavelength 635 nm between two glass plates separated by a wire. The equation used is 2d = (m + 1/2)λ, where d is the separation and m is the fringe order. The calculation yields m = 125.484, suggesting 125 fringes, but confusion arises regarding the total length of the plates, which is 16 cm. The discussion highlights the need to consider the geometry of the setup and how the length of the plates affects the number of observable fringes. Clarification on the relationship between m and the actual number of fringes is essential for accurate results.
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Homework Statement


Light of wavelength 635 nm is used to illuminate normally two glass plates 16 cm in length that touch at one end and are separated at the other end by a wire of radius 0.02 mm. How many bright fringes appear along the total length of the plates?



Homework Equations


http://www.phys.washington.edu/users/savage/Class_123/Assigns_123_99/***_99_6/soln99_6/node6.html <-- Same problem except with different numbers and it has a shows solution.

2d = (m + \frac{1}{2})*\lambda

2* 0.04mm = (m + \frac{1}{2}) * 635 nm

\frac{0.08 mm}{635 nm} = (m + \frac{1}{2})

125.984 = m + \frac{1}{2}

m = 125.484 or 125

yet I get the answer wrong
 
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Here m is not the number of bright fringes. What about the length 16 cm?
 
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