Solving Limits and Discontinuities: f(x)= 3x2-12x / x2-6x +8

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1. f(x)= 3x2-12x / x2-6x +8



f(x) can be made continuous at x =4 by defining f(4)=6

I know that the removable disc. is at x=2 and the non removable is at x=4. So there is an asymptote at x=4. How is it possible to define it there?
 
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You have that backwards. There's no asymptote at x=4. There's an asymptote at x=2. Find the limit as x->4. Show your work this time.
 
Ugh! Thanks I am just a fool and factored incorrectly. Final exams =(. Thank you !

3x(x-4) / (x-4)(x-2) = f(x)
So the lim as x-->4 f(x)=6
 
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