Solving Limits with Trig Functions

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I am having trouble solving limits with trig functions.

limx→0 x+xcosx/sinxcosx

useful equation limθ→0 sinθ/θ = 1

my attempt

x+xcosx/sinxcosx

x/sinxcosx + xcosx/sinxcosx

x/sinx*1/cosx + x/sinx this is where I am getting stuck
 
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the answer is right in front of you.

As x approaches zero then what is the value of cosx?

and you have the sinx/x as x approaches zero so everything is there for you
 
jedishrfu said:
the answer is right in front of you.

As x approaches zero then what is the value of cosx?

and you have the sinx/x as x approaches zero so everything is there for you


Does x/sinx = 1 also?

I thought sinx had to be in the numerator for it to = 1
 
TommG said:
Does x/sinx = 1 also?

I thought sinx had to be in the numerator for it to = 1

Technically, you're right. But note that if ##x\neq 0##, then ##\frac{x}{\sin x}=\frac{1}{\frac{\sin x}{x}}##, and you have something to which you can apply your limit law for ratios.

So I guess technically you're not right (with regard to the value of the limit), but it's good to be skeptical. I had some students a year or so ago that got marked down (per a grading rubric that was not mine) for omitting the step that I showed.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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