Solving Log6 36 = 5x+3: Can't get the Answer Right

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The discussion centers on solving the equation 6^(5x+3) = 36. The initial calculations lead to an incorrect conclusion of x = 1/5 due to a misplacement of the minus sign. Upon reevaluation, it is clarified that the correct solution is x = -1/5, as the calculations should reflect the negative sign. The importance of proper notation and careful checking of work is emphasized throughout the conversation. Ultimately, the correct answer is confirmed as x = -1/5, resolving the initial confusion.
Rusho
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I got an answer, but I cannot get it to check correctly:

=6 ^5x+3 =36
=6 ^5x+3 = 6^2
=5x+3 =2
=5x = -3+2
=5x = -1
x= 1/5

But I put 1/5 into the equation and it does not work out correctly.
 
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Check your work again. I think you'll laugh.
 
Rusho said:
I got an answer, but I cannot get it to check correctly:

this equality sign means??->=6 ^(5x+3) =36 Missing parentheses:mad:
(=)6 ^(5x+3) = 6^2
Totally incorrect use of equality sign! :mad:-> =5x+3 =2
Totally incorrect use of equality sign! :mad:->=5x = -3+2
(=)5x = -1
x= 1/5
Where did the minus sign go?
 
Without the equals

6 ^5x+3 =36
6 ^5x+3 = 6^2
5x+3 =2
5x = -3+2
5x = -1
5x/5 = -1/5
x= - 1/5

OH I see now I get "2" and 6^2 =36 :)
 
6^{5*(-\frac{1}{5})+3}=6^{-1+3}=6^{2}=36
your problem being?
 
Your problem was on the last lines:

5x = -1
x= 1/5


You forgot about the minus sign.
 
You should try being more negative. :smile: :smile:
 
Curious3141 said:
You should try being more negative. :smile: :smile:
:mad: :mad: :mad: :mad: :mad: :mad: :mad: :mad: :mad: :mad: :mad: :biggrin:
 
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