Solving Nature of Atoms Homework: Part (a) ionization energy Z=2

  • Thread starter Thread starter arod2812
  • Start date Start date
  • Tags Tags
    Atoms Nature
AI Thread Summary
The discussion focuses on calculating the ionization energy for an ionized atom with atomic number Z=2, specifically helium. For part (a), the minimum energy required to remove the electron from the ground state is sought, while part (b) involves determining the ionization energy. The user initially believed the answer for part (a) was 13.6 eV, which is incorrect as this value applies to hydrogen. The correct approach involves using the formula E = -13.6 * (Z^2/n^2), where Z=2 and n=1, indicating that the ionization energy for helium needs to be calculated accordingly. Understanding the distinction between ionization and excitation is crucial for solving these types of problems.
arod2812
Messages
25
Reaction score
0

Homework Statement


(a) What is the minimum energy (in electron volts) that is required to remove the electron from the ground state of an ionized atom (Z=2)? (b) What is the ionization energy for this ion?


Homework Equations


After doing what I got the answer for part (b)... but I don't know what part (a) requires. I thought this number would be 13.6 eV, but it's not. What exactly is part (a) asking?


The Attempt at a Solution



I used the equation E= -13.6*(Z^2/n^2). I plugged in 2 for Z and 1 for n.
 
Physics news on Phys.org
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top