Solving ODE dy/dx = (x+y)^2 , y(0)=1

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In summary, an ODE (ordinary differential equation) is a mathematical equation that describes the relationship between a function and its derivatives. To solve a first-order ODE, we can use methods such as separation of variables, integrating factors, or the method of undetermined coefficients. The initial condition, y(0)=1, helps us find the specific solution to the ODE. To find the general solution, we rearrange the equation, integrate, and add a constant of integration. The specific solution represents the particular solution that satisfies the initial condition. In this case, the specific solution is y = tan(x+C) where C is the constant of integration.
  • #1
mat331760298
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solve dy/dx = (x+y)^2 , y(0)=1

i let w = (x+y) and got the above equation rearranged to dw/dx - 1=w^2

after solving for C i got y=tan(x-pi/4) - x

just wanted to check my answer
 
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  • #2


w = (x+y) then
dw/dx = 1+dy/dx
dw/dx = 1 + w^2

this part looks ok
 
  • #3


then
w = x+y=x+(tan(x-pi/4)-x) = tan(x-pi/4)
dw/dx = sec(x-pi/4)^2 = 1+tan(x-pi/4)^2
 
  • #4


just remains to check IC
w(0) = tan(-pi/4)

does that look correct?
 

1. What is an ODE?

An ODE (ordinary differential equation) is a mathematical equation that describes the relationship between a function and its derivatives. In this case, the ODE is dy/dx = (x+y)^2.

2. How do you solve a first-order ODE?

To solve a first-order ODE, we can use a variety of methods such as separation of variables, integrating factors, or using the method of undetermined coefficients. In this case, we can use the method of separation of variables to solve dy/dx = (x+y)^2.

3. What is the initial condition in this problem?

The initial condition, y(0)=1, tells us the value of the function y at the point x=0. It is an important piece of information that helps us find the specific solution to the ODE.

4. Can you explain how to find the general solution to this ODE?

To find the general solution to this ODE, we first rearrange the equation to separate the variables x and y. Then, we integrate both sides and add a constant of integration. This will give us a general solution that includes all possible solutions to the ODE.

5. What does the specific solution represent in this problem?

The specific solution represents the particular solution to the ODE that satisfies the initial condition. In this case, the specific solution is y = tan(x+C) where C is the constant of integration.

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