Solving Oscillation Problem: Find Time for Pendulum with 30m Cable

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The discussion focuses on calculating the period of a pendulum with a 30m cable length. The formula used is T = 2π√(L/g), where L is the length of the cable and g is the acceleration due to gravity (9.81 m/s²). Initially, a participant calculated the period as 9.61 seconds but later corrected it to 11 seconds after realizing a calculation error. The conversation emphasizes the importance of accurate calculations in determining the period of simple harmonic motion. The final confirmed time for one complete oscillation is 11 seconds.
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A wrecking ball is suspended from a crane by a cable that is 30 m long. How much time is required for such a simple pendulum to make one complete oscillation? no picture was given to me

Ok this is a pendulum problem and its asking for time which is the period.

So I think that this formula should work since its a simple harmonic motion prob. and asking for Time.

T= 2pi[L/g]^1/2

T=2pi[30/9.81m/s]^1/2
T=9.61s

Is this correct or did I miss something.
 
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Well, the reasoning and the equation look fine, but I'm getting a different answer. You might check the calculation again.
 
yeah I made a calculation error. Now I got 11s as the time. Thanks Diane
 

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