Solving Part B of Homework Equation | Φ, EMF & V

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The discussion focuses on solving Part B of a homework equation involving magnetic flux (Φ), electromotive force (EMF), and voltage (V). The user calculated the magnetic flux using the area of the loop but misunderstood the transition to calculating EMF, which requires the rate of change of flux over time (dΦ/dt). Clarification was provided that the speed of the coil's movement relates to the change in area over time, as the area is defined by the dimensions of the loop. The user confirmed understanding that the speed equals the change in distance over time, which is crucial for calculating EMF. Overall, the conversation emphasizes the relationship between magnetic flux, area, and the motion of the coil in determining EMF.
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Homework Statement


Uploaded the question below , Part B

Homework Equations


Φ=NBA
EMF= (delta)Φ/(delta)t
V=IR

The Attempt at a Solution


so i found the area (0.25x0.3) and then divided by two (=0.0375m^2) , then found Φ=80x1.4x0.0375=4.2wb
However , in the marking scheme they multiplayed by the speed instead of area !
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So, you calculated ##\Phi##. But for the emf you need ##d\Phi\over dt##. Is the step from one to the other unclear to you ?
 
BvU said:
So, you calculated ##\Phi##. But for the emf you need ##d\Phi\over dt##. Is the step from one to the other unclear to you ?
i know i have to use dΦ/dt , that's why i calculated Φ .. couldn't get how they found 0.7v
 
Area with magnetic field within the loop is xy . x is constant, 0.25 m. At t=0 y = 0.15 m . When the coil is moving, y decreases by 2 m/s
 
BvU said:
Area with magnetic field within the loop is xy . x is constant, 0.25 m. At t=0 y = 0.15 m . When the coil is moving, y decreases by 2 m/s
so its like we make change of "y" over time equals to the speed ? since speed = distance covered / time taken
 
That is exactly what it is !
 
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