Solving PDE Homework Statement - Can You Help?

  • Thread starter Thread starter jahandideh
  • Start date Start date
  • Tags Tags
    Pde
jahandideh
Messages
7
Reaction score
0

Homework Statement



oh! after trying to re-solve a PDE I reached this:


Homework Equations


\sum\frac{4}{((2n-1)\pi)^2} (a+\frac{4(-1)^{n+1}}{(2n-1)\pi}) cos(\frac{2n-1}{2}\pi x)

n goes feom 1 to \infty and "a" is a constant value.

The Attempt at a Solution


the solution i am trying to reach is:

=\frac{1}{2} (1-x^{2}+(1-x)a)

but i don't know how?
can anyone help please?
 
Physics news on Phys.org
What is the Fourier series for \frac{1}{2} (1-x^{2}+(1-x)a)?
 
thanx for suggestion my buddy.
u know the orginal problem is a heat equation - one dimensional and time dependent-

T_{xx}+j^{2}=T_{t}
T_{t}=-1/2j\frac{b}{cL}
T(1,t)=0
T(x,0)=0

j,c,b are constant and 0\leqx\leq1

i solved the problem to here:

T(x,t)= j^{2} \sum (\frac{1}{\lambda_{n}^{2}}) \times \frac{b}{cL}+ \frac {2 \times -1^{n+1}}{\lambda_{n} cos(\lambda_{n}x + j^{2} \sum \frac{-1}{(\lambda_{n})^{2}}(e)^{-\lambda_{n}t} \left[\frac{b}{cL}+ \frac {2\times -1^{n+1}}{\lambda_{n}\right] cos(\lambda_{n}x)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top