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altrez
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Just two questions that are a small part of my ISU for physics. For this year we had to teach ourselves the unit on electricity and magnetism.
1. A bird stands on an electric tranmission line carrying 1200A. The line has a [itex]1.0\times10^{-5} \Omega[/itex] resistance per metre and the bird's feet are 30cm apart. What voltage does the bird feel.
2. What is the force per metre on a wirde carrying a 2.50A current when perpendicular to a 1.10T magenetic field.
For question one, I was first thinking that since the bird isn't grounded, it shouldn't really feel anything, but since the question probably wouldn't be as easy as that, i guess i'd have to calculate something.
Formula i used was just V=IR
[itex]V = (1200 A)(1.0\times10^{-5} \Omega)(3.0\times10^{-1}m)= 3.6 \times 10^{-3} V
[/itex]
That's what i got as a final answer
For question two, our books didn't really mention anything about formulas with the tesla unit so i guess we had to research it.
I found a formula that was :
[itex]B=\frac {F} {IL} \vspace[/itex]
B is 1.10T
I is 2.50 A
L i think would be 1m since they wanted the force per metre.
F is the unkown
So in the end i got [itex]F = BI
= 1.10T \times 2.50A =2.75 N/m
[/itex]
Just need some feedback on those questions.
1. A bird stands on an electric tranmission line carrying 1200A. The line has a [itex]1.0\times10^{-5} \Omega[/itex] resistance per metre and the bird's feet are 30cm apart. What voltage does the bird feel.
2. What is the force per metre on a wirde carrying a 2.50A current when perpendicular to a 1.10T magenetic field.
For question one, I was first thinking that since the bird isn't grounded, it shouldn't really feel anything, but since the question probably wouldn't be as easy as that, i guess i'd have to calculate something.
Formula i used was just V=IR
[itex]V = (1200 A)(1.0\times10^{-5} \Omega)(3.0\times10^{-1}m)= 3.6 \times 10^{-3} V
[/itex]
That's what i got as a final answer
For question two, our books didn't really mention anything about formulas with the tesla unit so i guess we had to research it.
I found a formula that was :
[itex]B=\frac {F} {IL} \vspace[/itex]
B is 1.10T
I is 2.50 A
L i think would be 1m since they wanted the force per metre.
F is the unkown
So in the end i got [itex]F = BI
= 1.10T \times 2.50A =2.75 N/m
[/itex]
Just need some feedback on those questions.
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