Solving Physics Motion: When Does Green VAN Overtake Red CAR?

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The discussion focuses on determining when a green van overtakes a red car in a physics motion problem. Participants emphasize the need to equalize displacements and suggest using equations of motion to find the solution. The conversation highlights the importance of understanding the relationship between velocity, time, and area under the graph for displacement. A breakthrough occurs when one participant successfully solves the problem after guidance on setting up the equations. The thread concludes with a sense of accomplishment as the solution is found.
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I'm having trouble with the 2nd part of this question, which asks at what instant the VAN (Green) overtakes the CAR (Red). I drew out the diagram. From what I believe, the displacements have to be equal so would I have to substitute two equations in each other?

http://img371.imageshack.us/img371/4530/diag2nj.png
 
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That's correct

marlon
 
I'm just lost on how to start the question...my friend and I are discussing it but bleh >_<
 
Well write down the equation of v as a function of time t.

You know that :
(30,15) and (0,0)
(60,20) and (0,0)

are the couples of points that belong to each linear curve.

Can you write down the equation of a linear function when these points have been given ?

marlon
 
well we're not supposed to use linear function...it's on agraph so it displacement would the area underneath the graph...still stuck on it.
 
Hollysmoke said:
well we're not supposed to use linear function...it's on agraph so it displacement would the area underneath the graph...still stuck on it.
i don't think you are getting the point.

Just set up v = a*t

by using y-y1 = \frac{y2-y1}{x2-x2}(x-x1)

The (x1,y1) and (x2,y2) have been given. Keep in mind that x is t and y is v here

Or you can indeed get the a by calculating the surface under the curve.

Anyhow, the result must stay the same.

marlon
 
Omg I Figured It Out. Thank You Marlon!
 
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