Solving Physics Problem: Calculate Frictional Force of 24 N

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To calculate the frictional force acting on a 5 kg mass on an inclined plane with a 24 N force causing acceleration of 3 m/s², the net force must be determined. The net force is calculated as the applied force minus the frictional force, equating to the mass times acceleration. The initial calculation suggested a frictional force of 9 N, but it was noted that the weight of the mass also contributes a component opposing the applied force. Therefore, the assumption about the direction of the applied force and the weight's effect on the net force must be clarified for an accurate calculation. Correctly accounting for these factors is essential for solving the problem.
Misr
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hi ,

1.A force of 24 N acts on a body causing its movement on an inclined plane with acceleration 3 m/s^2 . calculate the frictional force.



so can u illustrate the answer to me?

Thanks
 
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You will need to provide more information to allow us to help with this.
What is the mass in kg? The angle of the plane? The direction of the force?
 
You will need to provide more information to allow us to help with this.
What is the mass in kg? The angle of the plane? The direction of the force?

No , I just forgot to write the mass which is 5 Kg .This is the All of the Given information.
But for now i have a suggestion and all you have to do is to check w heather I'm right or not.

The net force acting on the system = The force causing the acceleration of the ball - Friction force
right??
well
Net force = 24 - Friction = (5*3)
Net force = 24 - Friction = 15
therefore friction force = 24 - 15 = 9 Newtons

Right??
Thanks in advance.
 
Misr said:
No , I just forgot to write the mass which is 5 Kg .This is the All of the Given information.
But for now i have a suggestion and all you have to do is to check w heather I'm right or not.

The net force acting on the system = The force causing the acceleration of the ball - Friction force
right??
well
Net force = 24 - Friction = (5*3)
Net force = 24 - Friction = 15
therefore friction force = 24 - 15 = 9 Newtons

Right??
Thanks in advance.
That looks good, provided that the applied 24 N force acts parallel to the plane. Since the problem does not specify that, I guess you'll have to assume it.
 
If the plane is inclined and the force acts parallel to it, the net force is not simply "24 - friction". The weight of the mass also has a component acting against the 24N.
 
Stonebridge said:
If the plane is inclined and the force acts parallel to it, the net force is not simply "24 - friction". The weight of the mass also has a component acting against the 24N.
Indeed it does, my error:redface:
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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