Solving Physics Question: Momentum Change of 0.42 kg Ball

  • Thread starter Thread starter draconicspectre
  • Start date Start date
  • Tags Tags
    Physics
AI Thread Summary
The problem involves a 0.42 kg ball moving at 5.5 m/s that rebounds at 2.0 m/s after hitting a wall. To find the change in linear momentum, the formula used is the difference between the final and initial momentum, expressed as (mv2 - mv1). The correct calculation shows that the change in momentum is 3.24 kg·m/s. Despite the simplicity of the problem, users are struggling with inputting the correct answer. Understanding the vector nature of momentum is crucial for solving this type of physics question.
draconicspectre
Messages
10
Reaction score
0
A 0.42 kg ball is moving horizontally with a speed of 5.5 m/s when it strikes a vertical wall. The ball rebounds with a speed of 2.0 m/s. What is the magnitude of the change in linear momentum of the ball?

Might seem like a simple problem, but everytime i input an answer into it, it says I am wrong, can neone help?
 
Physics news on Phys.org
draconicspectre said:
A 0.42 kg ball is moving horizontally with a speed of 5.5 m/s when it strikes a vertical wall. The ball rebounds with a speed of 2.0 m/s. What is the magnitude of the change in linear momentum of the ball?

Might seem like a simple problem, but everytime i input an answer into it, it says I am wrong, can neone help?

Since the change in linear momentum is a vector given by (mv2-mv1)i, its magnitude is the square root of (mv2-mv1)^2, which equals mv2-mv1. This should work.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »

Similar threads

Ambiguous question on momentum and how it works...
Replies
13
Views
1K
Work done during a collision -- Change in Kinetic Energy & change in Momentum
Replies
1
Views
2K
Golf club 🏌️and ball ⛳ impulse problem
Replies
19
Views
2K
Why momentum of a ball bounced off a wall increases twice fold?
Replies
9
Views
4K
How to Calculate Speed of Head of Driver After Collision?
Replies
10
Views
2K
Solving a Ball Thrown off a Cliff: How Long Does it Take?
Replies
4
Views
2K
How to calculate rebound speed of ball hitting a wall?
Replies
4
Views
6K
Which Force is Represented by the Gradient of the Ball-Wall Collision Graph?
Replies
3
Views
4K
A ball bounces off a brick wall, Find the average acceleration
Replies
5
Views
5K
Swinging Ball at Top of Circle: Forces & Energies
Replies
16
Views
2K

Hot Threads

Recent Insights

Back
Top