Solving PV/nRT for T: Temp Needed to Reduce Gas Volume to 2.50L

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To solve for the temperature needed to reduce the volume of sulfur hexafluoride gas from 5.10 L to 2.50 L at constant pressure, the ideal gas law equation PV=nRT is applied. The initial temperature of 198 C must be converted to Kelvin for accurate calculations. The resulting temperature calculation yields a value of -42 C, but this is incorrect if the initial temperature is used in Celsius. Proper conversion to Kelvin is essential to avoid errors in the final temperature result. Accurate application of the ideal gas law ensures correct temperature determination for the specified volume change.
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A sample of sulfur hexafluoride gas occupies a volume of 5.10 L at 198 C. Assuming that the pressure remains constant, what temperature (in C) is needed to reduce the volume to 2.50 L?

I used PV/nRT = PV/nRT and got -42 C.

Do I have to convert to Kevlin first and then back to Celsius?
 
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You would have to convert to Kelvin. Whether to express you answer in Celsius is a matter of prefrence, but your answer will come out in Kelvin.
 
fromthepast said:
Do I have to convert to Kevlin first and then back to Celsius?
It looks like this is what you did already. You won't get -42 if you use initial temperature in Celsius.
 
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