Solving Recurrence Relation w/ Initial Conditions for n-digit Sequences

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The discussion focuses on finding a recurrence relation for n-digit sequences using the alphabet {0, 1, 2, 3, 4}, specifically requiring at least one '1' before any '0'. The proposed recurrence relation is based on the assumption that the sequence can start with any of the digits, leading to the expression 3a(n-1) + 5. Initial conditions are suggested as a(0) = 1 and a(1) = 1. The final expression for the solution is presented as 3n-1 + 5n-1 + a(n-1). The user seeks a step-by-step explanation to better understand the problem for an upcoming test.
hyderman
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hello

any one can help me with this question

thanx

(a) Find a recurrence relation for the number of n-digit sequences over the alphabet {0, 1, 2, 3, 4} with at least one 1 and the first 1 occurring before the first 0 (possibly no 0’s).

(b) What are the initial conditions?

(c) Solve the recurrence relation in Part (a) satisfying the initial condition
 
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a) we have property starts with 0,1,2.3.4
so there are n-1 digits of sequence
sio i think the recurrence should be 0+(an-1)^3times therefore
3an-1 + 5


b) initial condition a0=1 and a1=1

c) 3n-1+ 5n-1 + an-1


please i just need some one to explain this in steps ... this type of question will be in the test and i am not sure how to solve it

thanx
 
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