Solving Resistor Problems: How to Find Equivalent Resistances

  • Thread starter Thread starter robphysics
  • Start date Start date
  • Tags Tags
    Resistors
AI Thread Summary
To find the equivalent resistances of four 45-ohm resistors, there are ten possible configurations, which can be derived through various combinations of series and parallel arrangements. The simplest approach is to draw out the circuits to visualize each configuration, starting with all resistors in parallel and transitioning to all in series. Mathematically, the arrangements can be categorized: one for all in parallel, two for three in parallel with one in series, six for two in parallel with two in series, and one for all in series. This systematic breakdown confirms that there are indeed ten unique arrangements. Ultimately, visualizing the circuits aids in understanding the equivalent resistances more effectively.
robphysics
Messages
2
Reaction score
0
Four resistors all have resistance 45 W . Find all the possible equivalent resistnaces that can be created (there are ten) and list them from largest to smallest equivalent resistance.

Is there a way to solve this mathmatically or do i have to draw out the 10 circuits and figure it out that way?
 
Physics news on Phys.org
Yes.

I think you want to do the second option, it would be easier. Just start with all four in parallel and change one at a time to end up with four in series.
 
Could you point me in the right direction for solving it mathematically?
Thanks
 
Well.. The best way that i still think is the best is to draw out all 10 cicuits.. However, you can still try to do this using some maths.

Let's not make this too complicated.. Split up the types of arrangements first.
Let resisitors in parallel be considered as 1 resistor.
Therefore, we have:
...4R...3R...2R...1R...
....|...|...|...|...
...1...1...1...1...

For 4 resistors in parallel, we have only 1 type of arrangement(4 R in Parallel)

For 3 resistors in parallel, we will have 2 types of arrangement (1 R in series with the other 3 R in parallel)(Rotate bout the positions of the resistors in series to get 2)/ You can also permute 2 with 2..

For 2 R in parallel, we will have 6 types of arrangement (2 R in series with the other 2 in parallel) Taking the 2 parallel R as 1 R, Permute the 3 R with the 3 slots. ie: 3P3=6

For all resistors in series, we will have only one type of arrangement.

Therefore adding all arrangements.. 1+2+6+1=10!
 
Last edited:
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top