- #1
MillerL7
- 14
- 0
The velocity function is v(t)=t^2 -5t + 6 for a particle moving along a line. Find the displacement traveled by the particle during the time interval [0,5].
What is the displacement?
What is the distance traveled?
I think that the information should look like this:
(1)(1^2 -5(1) +6)+(2)(1^2-5(2)+6)+(3)(1^2-5(3)+6)+(4)(1^2-5(4)+6)+(5)(1^2-5(5)+6) to get the distance..., but I am unsure about it.
What is the displacement?
What is the distance traveled?
I think that the information should look like this:
(1)(1^2 -5(1) +6)+(2)(1^2-5(2)+6)+(3)(1^2-5(3)+6)+(4)(1^2-5(4)+6)+(5)(1^2-5(5)+6) to get the distance..., but I am unsure about it.