Solving Rotation Matrices Urgently: cos(pi/4) -sin(pi/4) sin(pi/4) cos(pi/4)

AI Thread Summary
The discussion focuses on understanding rotation matrices, specifically the matrix for a 45-degree rotation represented by cos(pi/4) -sin(pi/4) and sin(pi/4) cos(pi/4). The user expresses confusion about a follow-up question related to a matrix that not only rotates but also doubles the length of a vector. A contributor clarifies that the provided matrix is indeed a rotation matrix, emphasizing its property of preserving vector length. The main goal is to find a matrix that achieves both rotation and length doubling. The conversation highlights the importance of distinguishing between rotation and scaling in matrix transformations.
rrm74001
Messages
1
Reaction score
0
[URGENT] Rotation Matrices

Homework Statement



http://e.imagehost.org/0661/Screen_shot_2010-03-09_at_12_37_44_AM.png

Homework Equations



Rotation Matrix:
cos(theta) -sin(theta)
sin(theta) cos(theta)

The Attempt at a Solution



I understand 2a:

cos(pi/4) -sin(pi/4)
sin(pi/4) cos(pi/4)

But I am not sure what 2b is looking for. Please help?

Thank you in advance for your help!
 
Last edited by a moderator:
Physics news on Phys.org


The matrix you wrote is a rotation matrix, which rotates a vector but leaves its length unchanged. You need a matrix which doubles the length as well. Try to find such one. ehild
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top