Solving schrodinger equation for quarkonium

nasibaba
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I've tried to solve Schrodinger equation for Charmonium and Bottomonium and there are some problems with that :

1. As we know the Schrodinger equation is independent from quantum number "ml" so there would be same Energy for different "ml" for a specific n. But what we see in PDG book is some how confusing, according to this book the mass of states with different "ml" are not equal !
Why this happens and what does it mean ?

2.How can I do the same with dirac equation?! Is there any specific code ?

thanx
 
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The different energy levels of quarkonium are due to spin-orbit coupling. The two quark spin 1/2's can couple two ways: S = 0 and S = 1. If for example we take L = 1, the different energy levels will be 1P1 for S = 0, and 3P0, 3P1 and 3P2 for S = 1, J = 1, 2, 3.
 
First, thank you bill for answering me

I know what you've said but they are eigenvalues !
So there wouldn't be any difference in the mass !

Or I'm wrong :(
 
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L and S have definite values for each state, since they commute with the Hamiltonian. That just means you can label the states according to the eigenvalues of L and S. However since the Hamiltonian depends on S1·S2 and L·S, each state has a different energy. This is analogous to the line splitting you find in other systems, like atoms and also in positronium.
 
oh, I got it :)

really really thank you
 
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