Solving Shunt Series-Series Feedback Problem: Help Needed | Angelfire

  • Thread starter Thread starter geelude
  • Start date Start date
  • Tags Tags
    Feedback
AI Thread Summary
The discussion focuses on solving a shunt series-series feedback problem in amplifier design. Key points include the role of negative voltage feedback in stabilizing closed-loop gain and its advantages in reducing nonlinear distortion and noise. It highlights the importance of feedback in defining input and output impedances, with shunt feedback lowering impedance and series feedback increasing it. The conversation also addresses the potential for oscillation in feedback circuits if not carefully designed, emphasizing the need for gain roll-off in amplifiers to maintain stability. Overall, the insights aim to enhance the understanding of feedback networks in amplifier applications.
geelude
Messages
1
Reaction score
0
Hey guys,

I am currently solving a problem involving shunt series-series feedback. So far this is what I can say about the circuit:

- Series mixing is feedback combined with source
- Negative voltage feedback samples output voltage
- Series voltage feedback stabilises close loop gain and should be used to get precise voltage gain
- Negative feedback has disadvantage of reducing gain of amp but can be overcome by extra stages of amplifier
- Advantages are stabilises gain, reduction in nonlinear distortion, reduction in noise and also controls input and output impedance
- Unwanted noise coming from power supply, coupling of signals from other circuits, feedback can only reduce thermal and shot noises
- In voltage feedback input terminals of the feedback network are in parralel with the load and output voltage appears at the input terminal of feedback
- A way to test for voltage feedback is to see if signal vanishes as short circuit
- As series voltage feedback stabilises close loop voltage gain it is good for designing amplifiers with precise voltage gainse
- Negative feedback factor is larger than unity therefore negative series feedback increases input impedance
- Negative voltage feedback reduces output impedance


Can anyone else help me out, what else can I add and say about this feedback network?

The link to the problem is as follows:

http://www.angelfire.com/electronic2/helpneed/index.html

Please help!

Thanks!
 
Engineering news on Phys.org
extra and important point

In many circuit applications feedback is used to help fix input and output impedances . Typically shunt will reduce the impedance to low values , so that an external but well defined resistor then defines the (say ) input impedance.
Series does the opposite
. It is possible to use a combination to define an accurate matching impedance (say 50 ohms) without ever using a 50 ohm resistor and hence gain a noise advantage.
One of the most important uses is to linearise a circuit -- most transistor circuits are inherently non-linear ( not all) -- the transfer funtion io/vi
is partly diode characteristic dependant ( exponential ) but also beta dependant ( i.e. transfer efficiency ) , so that for linear applications ( Audio amplifiers , or instrumentation ) you must use feedback to overcome this.
The limitations of these techniques is that unless carefully designed they can oscillate , to avoid this the internal amplifier is usually rolled off in gain at a 6db/octave rate -- Opamps are a good example where a single capacitor dominates the roll off .
This has the effect of reducing the amount of feedback with frequency
so severly limits the 'useful' range where the feedback is effective.
 
Hi all I have some confusion about piezoelectrical sensors combination. If i have three acoustic piezoelectrical sensors (with same receive sensitivity in dB ref V/1uPa) placed at specific distance, these sensors receive acoustic signal from a sound source placed at far field distance (Plane Wave) and from broadside. I receive output of these sensors through individual preamplifiers, add them through hardware like summer circuit adder or in software after digitization and in this way got an...
While I was rolling out a shielded cable, a though came to my mind - what happens to the current flow in the cable if there came a short between the wire and the shield in both ends of the cable? For simplicity, lets assume a 1-wire copper wire wrapped in an aluminum shield. The wire and the shield has the same cross section area. There are insulating material between them, and in both ends there is a short between them. My first thought, the total resistance of the cable would be reduced...
I am not an electrical engineering student, but a lowly apprentice electrician. I learn both on the job and also take classes for my apprenticeship. I recently wired my first transformer and I understand that the neutral and ground are bonded together in the transformer or in the service. What I don't understand is, if the neutral is a current carrying conductor, which is then bonded to the ground conductor, why does current only flow back to its source and not on the ground path...
Back
Top