Solving Simple Harmonic Motion Problems| Physics HW

AI Thread Summary
The discussion focuses on solving a simple harmonic motion problem involving a bullet colliding with a block of clay, which results in a perfectly inelastic collision. Participants clarify that while energy is not conserved due to the collision, linear momentum is conserved, allowing for the calculation of the final velocity using the formula for momentum. The spring's potential energy is not relevant immediately after the collision since it is not compressed, and thus does not affect the velocity at that moment. The conversation emphasizes the importance of understanding the timing of forces and energy in the context of the problem. Ultimately, the participants successfully arrive at a solution with guidance on the necessary concepts.
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Homework Statement



http://www.physics.umd.edu/courses/Phys122/Noyes/HW/hw1.pdf (pg 3)

Homework Equations



Im guessing that E = K + U has something to do with it


The Attempt at a Solution



Not really sure where to start..I tried a few approaches but none of them got me anywheres E = 1/2mv^2 + 1/2 kx^2..but I am missing too many things..

Any help?
 
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when the bullet colides, it sticks. This means that energy is not conserved but something else is.
 
by the way, the fact that the clay sticks and that the collision is therefore perfectly inelastic is one of those "assumptions"
 
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conservation of linear momentum?
 
yes. now you can use that in combination with energy.
 
so I have \frac{mv +Mv_2}{m+M} = v_f where Mv_2 is going to be 0 since it is at rest?

and E=1/2mv^2 + 1/2kx^2

Do i let m = m+M? and will 1/2kx^2 be 0 since the block can be considered to be at point x=0?...set it to zero and solve for v?
 
you actually don't need to use energy until you are ready to find the amplitude. You already have enough information to find the velocity.
 
So imediately after the collision, the spring has no effect on the velocity?
 
that's correct. two ways to understand that
1) imediately after colision, spring is not compressed and therefore applies no force.

2) even if it were compressed, a force causes an acceleration which only changes velocity of some period of time.
 
  • #10
Solved it..Thanks for the help
 
  • #11
good job, np
 
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