Solving simultaneous equations F = ma

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Homework Help Overview

The problem involves Luke standing on a scale in an elevator with constant upward acceleration, where the scale readings change when he picks up a box. Participants are tasked with finding the elevator's acceleration and Luke's weight using the readings provided.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss formulating equations based on the scale readings before and after Luke picks up the box. There are attempts to express Luke's weight and the elevator's acceleration through simultaneous equations. Some participants express confusion regarding unit consistency and the validity of their equations.

Discussion Status

There is ongoing exploration of different approaches to solve for the unknowns. Some participants suggest focusing on individual readings rather than combining equations, while others are trying to clarify their equations and the relationships between the variables involved.

Contextual Notes

Participants note issues with unit consistency and the need for careful symbolic manipulation. There is a recognition of the assumptions made regarding gravitational acceleration and the conditions of the problem.

Jbreezy
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Homework Statement



Luke stands on a scale in an elevator which has a constant acceleration upward. The scale reads 0.97 kN. When Luke picks up a box of mass 20 kg, the scale reads 1.18 kN. (The acceleration remains the same.) (a) Find the acceleration of the elevator. (b) Find Luke's weight.

Homework Equations


So I came up with 2 equations one for Luke w/o the added mass one for Luke with.
W_1 = m(g+a) I solve it for m.
m = W_1 / (a+g)
equation 2
W-2-(m+20)g=(m+20)a

The Attempt at a Solution


My strategy is to just solve both equation for m. Set them equal and then just plug and chug and get my my a. The issue is I can't solve the equation!
If my strategy is correct. The units don't work out at all. Apples and Oranges.
So,

W_2 - 20g - 20a / a+g =W_1/ a+g
Multiply both sides by a+g gave
W_2 - 20g -20a = W_1
Cleaning it up for a I got...

W_2 -20g - W_1 / 20 = a
See what I meant about apples and oranges something is wrong. I have been at it for a while I have tunnel vision.
Thanks to whoever helps
 
Last edited:
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Jbreezy said:

Homework Statement



Luke stands on a scale in an elevator which has a constant acceleration upward. The scale reads 0.97 kN. When Luke picks up a box of mass 20 kg, the scale reads 1.18 kN. (The acceleration remains the same.) (a) Find the acceleration of the elevator. (b) Find Luke's weight.


Homework Equations


So I came up with 2 equations one for Luke w/o the added mass one for Luke with.
W_1 = m(g+a) I solve it for m.
m = W_1 / (m+g)
What kind of solution for m is that??
 
I changed it I just meant m = W_1/ (a+g)
That is it. Sorry typo. Good catch.
 
I suggest you look at the problem without trying to solve for both weights simultaneously.

You know the scale readings before and after Luke picks up the 20 kg box.
Assuming the accel. in the elevator is the same for both scale readings, and assuming a typical g, then you should be able to find the acceleration of the elevator.
 
Hello StemKind,
I was actually not just solving for the weights. I know what the weights were. But you are saying I should be able to get this without combining my equations?
Thanks,
 
Jbreezy said:
I changed it I just meant m = W_1/ (a+g)
That is it. Sorry typo. Good catch.

Substitute into your W_2 equation to find a. Then get m.
 
yeah that is what I tried above the units are not correct. That is the strategy but something is wrong with my solution above.
 
Jbreezy said:
W_2 -20g - W_1 / 20 = a
Two things will help here. Include parentheses and either include units throughout or, better, keep everything symbolic until the end. E.g. if mb is the mass of the box (20kg):
(W2 -mbg - W1) / mb = a
... and everything's apples.
 
Ahh Thank you Haruspex.
Apples are quite good. Especially with peanut butter. I see the issue now.
 

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