Solving Spherical Capacitor Problems: Step-by-Step Guide

AI Thread Summary
To solve the spherical capacitor problem, Gauss' law is essential, particularly in relation to the dielectric material. The electric field for a dielectric is expressed as E = Q / (4πkε₀r²), while the inner conductor's electric field uses E = 1 / (4πε₀) * Q / r². A calculation yielded an electric field of 3.25 x 10^-9, but the challenge remains in addressing the outer shell with the provided charge density. Incorporating the relative permittivity (er) of 1.8 into the dielectric field equation is crucial for accurate results. Further clarification on these points will aid in solving the problem effectively.
mopar969
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I need help on starting and solving this problem. See attachment for problem.
 

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Do you know Gauss' law?
 
yes.
 
mopar969 said:
yes.

In that case, use Gauss' law to attempt this problem, and post your attempt here. We can't just give you the answers without some effort on your part towards a solution.
 
I know that gauss law says q over epsilon zero but how do I incorporate this for the dielectric material?
 
I know that the electric field for a dielectric is e = Q all over 4 pi k epsilon zero r^2. I also know that the electric field for the innerest conductor can be found using E = 1 over 4 pi epsilon zero time Q over r^2. Using this equation I got 3.25 x 10 ^ -9. However I do not know how to solve the outer most shell given with the charge per volume value. And for my dielectric electric field formula how do I get the er value of 1.8 that was given in the problem into the equation?
 
Anybody have a way to solve this problem?
 

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