Solving Spring Force Problems: Showing Maximum Displacement & Velocity

aboutguava
Messages
2
Reaction score
0
I'm just having some trouble with this problem. Any help would really be appreciated. I'm not even sure where to start.

A spring (not ideal) supplies a force given by F = zx^2, where x is measured from the equilibrium position and z is a constant. A mass m is attached to the spring and then released from rest at x = 0 (non-stretched spring)

a) show that the maximum downward displacement of the mass will be (3mg/z)^(1/2)
b) At what displacement will the mass have its maximum velocity

Thank you
 
Last edited:
Physics news on Phys.org
Start by deriving the spring potential energy as a function of displacement x. (Hint: How much work is required to stretch the spring?)
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top