Solving Static Charge: Calculating Excess Electrons (-18 μC)

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To calculate the number of excess electrons corresponding to a static charge of -18 microcoulombs, one must first know the charge of a single electron, which is approximately -1.6 x 10^-19 coulombs. By dividing the total charge of -18 x 10^-6 coulombs by the charge of one electron, the result indicates that the body has acquired approximately 1.125 x 10^14 excess electrons. This calculation demonstrates the significant number of electrons involved in even a small static charge. Understanding static electricity and the movement of electrons is crucial for grasping concepts in physics. Accurate calculations are essential for solving problems related to static charge.
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Homework Statement


On a dry day, your body can accumulate static charge from walking across a carpet or from brushing your hair.

If your body develops a charge of -18 (microcoulombs), how many excess electrons has it acquired?






The Attempt at a Solution


i don't know what to do lol.
 
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Step 1, look up the charge of an electron.
 
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TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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