Solving Statistics Problem: Proving at Least 2 People with Same Hair Count

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In a city of 10 million people, where the average human has 110,000 hairs, it can be proven that at least two individuals must have the same hair count. The discussion references the Pigeonhole Principle, which states that if there are more items than containers, at least one container must hold more than one item. Given that the maximum number of distinct hair counts is limited (likely fewer than 110,000), this principle applies. Therefore, with 10 million people, it is impossible for everyone to have a unique hair count. This confirms that at least two people will share the same number of hairs.
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Homework Statement



There is a city with 10 million people and an average human has 110 000 hairs. Prove that there is at least 2 people with the same amount of hair.

The Attempt at a Solution



I really have no idea of how to even start solving this problem. Sorry.

Also, sorry for the bad english.
 
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Taturana said:

Homework Statement



There is a city with 10 million people and an average human has 110 000 hairs. Prove that there is at least 2 people with the same amount of hair.

The Attempt at a Solution



I really have no idea of how to even start solving this problem. Sorry.

Also, sorry for the bad english.

Is it possible to have 10 million people, all of whom have different numbers of hairs?

RGV
 

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