Solving Stick Thrown in Air with Initial Condition

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The discussion revolves around a physics problem involving a stick thrown into the air with its closest end having zero speed at release. The student is unsure about the initial orientation of the stick and how to interpret the condition that the closest end remains stationary. It is suggested that for the center of mass to rise, the nearest point must move downward, implying a horizontal position at the moment of release. The conversation emphasizes the importance of visual aids in understanding the problem better. Clarifying these initial conditions is crucial for accurately determining the height the center of mass will rise.
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Homework Statement



A student throws a stick of length L up into the air.At the moment it leaves her hand the speed of stick's closest end is zero.The stick completes N turns just as it is caught by student at initial release point.What is the height 'h' that center of mass rise ?

Homework Equations



v=ωr

The Attempt at a Solution



I think I can proceed with the problem but feel a little unsure about the initial orientation of the stick just as it leaves the hand and the initial condition that the the speed of stick's closest end is zero .

Could somebody reflect on how to interpret the initial condition given in the problem ?

Thanks
 
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I would think that if the centre of mass was to go up, the only way that the point nearest the hand could be moving relative to it would be downwards in order for it to be stationary. I.e. Not left or right.
 
Do you mean the stick is horizontal at the instant it leaves the hand ?
 
See figure.

ehild
 

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Hi ehild...

Someone has rightly said "A picture is worth a thousand words " .

Thanks...
 
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