Solving the Concave Lens Problem for a Hotel Room Peephole

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SUMMARY

The discussion centers on solving the Concave Lens Problem for a hotel room peephole, specifically using a 0.86 cm concave lens that reduces the size of the image by a factor of 0.01. The power of the lens is determined using the formula for lens power, which is the inverse of the focal length. The image location cannot be precisely calculated without knowing the object distance, denoted as do, but it can be described in relation to the lens. The magnification formula, m = -di/do, is also relevant for determining image characteristics.

PREREQUISITES
  • Understanding of concave lens properties
  • Familiarity with lens power calculation
  • Knowledge of magnification formulas
  • Basic optics concepts, including object and image distance
NEXT STEPS
  • Study the calculation of lens power using focal length
  • Explore the magnification formula in detail, specifically m = -di/do
  • Learn about the characteristics and applications of concave lenses
  • Investigate the use of simple microscope formulas in optics
USEFUL FOR

Students and professionals in optics, physics educators, and anyone interested in understanding lens behavior and calculations related to concave lenses.

itsgood819
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A certain 0.86 cm lens is used in a peephole for hotel room doors for safety reasons. The tenant sees the maid in the peephole but she is reduced in size by a factor 0.01.

A. What type of lens must be used?
B. Where is the image of the maid located?
C. What is the power of this lens?


The attempt at a solution
From the given, I assumed it was a concave lens. Focal length would equal 0.86 cm, and magnification would equal 0.01? How would I do part B? I started out using the m= -di/do but got stuck.

Also, what is the equation for the power of lens?

Thank you for your help!
 
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itsgood819 said:
From the given, I assumed it was a concave lens. Focal length would equal 0.86 cm, and magnification would equal 0.01? How would I do part B?

Since you're not given the distance to the maid, you can't figure out exactly where the image is. However, if you call this distance do, can you describe where the image is with respect to the lens?

Also, what is the equation for the power of lens?

It's just the inverse of the focal length. Remember that by convention, focal length is positive for convex lenses and negative for concave ones.
 
can we use the formula for magnification of simple microscope in terms of focal length and the least distance of distinct vision?
 

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