Solving the Energy Conservation Equation for Flywheel & Mass

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The discussion centers on deriving the relationship between the distance fallen (h) and the velocity (v) of a mass attached to a flywheel using energy conservation principles. The scenario involves a 2kg mass that causes the flywheel to rotate as it falls, with specific parameters including a flywheel radius of 120mm. Participants express difficulty in connecting their calculations to the given equation h = v^2(0.051 + 1.77I), questioning whether the issue lies in the equation itself or their understanding of concepts like Moment of Inertia and energy in rotating systems. The conversation highlights the importance of accurately applying conservation of energy to solve the problem. Overall, the discussion seeks clarity on the relationship between linear and rotational motion in this context.
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1. A flywheel about a string is wrapped. At the end of the string is a mass, 2kg, which is initially held staionary at the datum position. If the mass is released it will fall causing the flywheel to rotate, and after the mass has fallen a distance of h meters it has a linear velocity of v m/s whislt the flywheel the flywheel has a rotational velocity of W rad/s

The mass of the object is 2Kg, and the radius of the flywheel is 120mm. By using the principle of conservation of energy, show that the distance fallen, h, and the velocity, v, of the mass and the distance are related by the equation: h=v2(0.051+1.77I)



2. h=v2(0.051+1.77I)



3. I have made several attempts at this but I can't seem to find a relationship with the equation, is it the equation or is it just me?
 
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Are you familiar with the Moment of Inertia, and what the energy is for a rotating mass?
 

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