Solving the Gravitational Problem: Rocket Speed at Great Distance from Earth"

  • Thread starter Thread starter SELFMADE
  • Start date Start date
  • Tags Tags
    Gravitational
AI Thread Summary
A rocket launched from Earth's surface at 15,000 m/s will experience a change in speed as it moves away from Earth. The escape velocity from Earth is 11,200 m/s, meaning the rocket exceeds this speed upon launch. However, determining the speed at a great distance from Earth requires considering gravitational effects and energy conservation. The initial kinetic energy and gravitational potential energy must be balanced to find the final speed. Therefore, the problem emphasizes the need for a deeper understanding of gravitational dynamics rather than a simple calculation.
SELFMADE
Messages
80
Reaction score
0

Homework Statement



A rocket is launched straight up from Earth surface at 15000 m/s speed. What is the speed of the rocket when its very far away from the earth?

Homework Equations





The Attempt at a Solution



Escape speed from Earth is 11200m/s. So I am guessing the rocket's speed when its "very far" away from Earth is 3800m/s?
 
Physics news on Phys.org
Nice try, but no, that's not the answer. This problem is not quite that simple.

Think about this: how do you calculate the escape velocity, 11200 m/s? That should give you a clue as to how to proceed with this problem.
 

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Velocity required to escape the solar system
Replies
15
Views
1K
Time dilation and length contraction for a rocket
Replies
12
Views
3K
Motion of a rocket with propellant exhaust gas speed = constant
Replies
6
Views
1K
How Long for a Beam of Light to Reach Earth?
Replies
21
Views
1K
Universal Gravitation problem, help with final statement.
Replies
18
Views
2K
Rocket thrust force calculation
Replies
9
Views
2K
Finding the net gravitational force on a rocket....
Replies
5
Views
2K
Why is the thrust equation same under gravitational force?
Replies
10
Views
2K
Rocket Speed: Calculating from Ciolky's Number C
Replies
11
Views
1K
An object is launched from the Earth to escape the Sun
Replies
5
Views
2K

Hot Threads

Recent Insights

Back
Top