Solving the Inelastic Collision of 3 Balls

Click For Summary
SUMMARY

The discussion focuses on solving an inelastic collision problem involving three balls with specific masses and velocities. The user correctly applies the conservation of momentum equations in both the x and y directions, ultimately determining the initial velocity of Ball 2 to be 13.11 m/s and the angle θ to be 15.2 degrees. The user initially struggled with the sign conventions for the velocities but resolved the issue, leading to the correct answer. The solution emphasizes the importance of accurately setting up the problem and maintaining proper sign conventions in momentum calculations.

PREREQUISITES
  • Understanding of inelastic collisions in physics
  • Familiarity with momentum conservation principles
  • Knowledge of trigonometric functions and their application in physics
  • Ability to solve equations involving multiple variables
NEXT STEPS
  • Study the principles of inelastic collisions in detail
  • Learn how to apply conservation of momentum in two dimensions
  • Practice solving problems involving trigonometric functions in physics
  • Explore common mistakes in momentum calculations and how to avoid them
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and collision problems, as well as educators looking for examples of inelastic collision scenarios.

kk727
Messages
54
Reaction score
0

Homework Statement



2ur1lwy.png


Ball 1: 3kg, 7 m/s initially
Ball 2: 4kg, V m/s initially
Ball 3: 5kg, 10 m/s initially

Find V if the system collides inelastically and moves off at 2 m/s at 5 degrees above the horizontal.

Homework Equations



p + p = p + p (in both x and y directions)

The Attempt at a Solution



I set up the equations for momentum in both directions (sin and cosine). I ended up with 4v*sinθ = 13.7558 and 4v*cosθ = 50.608. I then solved for θ and got 15.2 degrees and an initial velocity for Ball 2 of 13.11 m/s. I don't believe this is the answer my teacher had in class.

My only question is, when setting up the problem, would you consider the velocity of Ball 3 to be negative? That's how I calculated it. I have no problems with the calculations, just the setting up of the problem. I didn't write all of my work down, but it was something like this:

(sin 15)(7)(3) + (sin θ)(v)(4) + (5)(-10)(sin 20) = (2)(sin5)(12)

And I simplified it, did the same for cosines, solved for θ, and then plugged into solve for V.

Am I way off?

:/
 
Physics news on Phys.org
(sin 15)(7)(3) should be negative, too - the vertical component is down.
 
Thank you! I realized I had my signs all wrong...stupid mistake! I figured it out and got the right answer!
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
961
Replies
10
Views
3K
Replies
9
Views
3K
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K