Solving the Mountain Climber Problem: Tension & Contact Force

AI Thread Summary
The discussion revolves around solving the mountain climber problem involving tension in a rope and contact force exerted by the wall. The climber weighs 780 N, and the rope is positioned at a 15° angle to the wall, creating a force triangle. Participants express confusion about finding the tension in the rope while already calculating the contact force at 209 N. The solution involves understanding the relationship between the forces and using the concept of moments to determine the tension based on perpendicular distances. Clarifying these concepts is essential for accurately solving the problem.
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Homework Statement



A mountain climber is rappelling down a vertical wall. The rope attaches to a buckle strapped to the climber's waist 15 cm to the right of his center of gravity and makes an angle of = 15° with the wall. The climber weighs 780 N.
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(a) Find the tension in the rope
N

(b) Find the magnitude and direction of the contact force exerted by the wall on the climber's feet.

Magnitude 209 N
Direction ____ ° above the horizontal.



Homework Equations


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The Attempt at a Solution



when finding the tension of the rope, how is it possible that I found the magnatude of the feet against the wall and couldn't find the tension of the rope? Arent they part of the same equation?

Is this like a fulcrum problem?
 
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You need to find the component of the reaction at right angles to the wall.
You have the force downward (weight) and so the magintude of the tension is just the long side of the force triangle - like the length of the rope in the diagram.
 
Thats not the right answer though I have already tried it.
 
"The moment of a force about a point is equal to the force times the perpendicular distance from the line of action of the force to the point"

Using this rule and what you have been told, you need to get the tension in terms of a 'perpendicular distance'.
 
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