Solving the Mystery of Convergence: \sum_{k=2}^{\infy}(\frac{1}{ln(k!)})

Emil_
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Homework Statement


I need help to decide if the series below are convergent or divergent.

<br /> \sum_{k=2}^{\infy}(\frac{1}{ln(k!)})<br />

Homework Equations



The Attempt at a Solution


I tried using the d'Alembert ratio test but the ratio is 1 if I calculated it correctly and then nothing can be said about the series.
 
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Thank you. I'll take a look on Raabe's test and see if I can work it out, but I'm pretty sure it could be done by another test since the course I'm taking doesn't teach Raabe's test.
 
have you heard of stirlings approximation?
 
lanedance said:
have you heard of stirlings approximation?

I think my teacher mentioned briefly an exact formula for n!, involving integrals of arctan etc. He said that the formula was rare even though it was derived 100 years ago, but I've not heard of stirlings approximation. However I think I can solve it using stirlings approximation, thank you!
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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