Solving the Physics Behind a Reddit Comic: Can the Raptor Catch Up?

  • Thread starter Thread starter winowmak3r
  • Start date Start date
  • Tags Tags
    Physics
AI Thread Summary
The discussion centers on analyzing a comic involving a raptor's speed relative to a person's running speed using physics concepts, particularly the Doppler effect. The calculations indicate that the raptor's war cry travels at the speed of sound, leading to a wavelength of approximately 0.27007 m per cycle. The derived velocity of the raptor is 7.2 m/s, which is lower than the assumed human speed of 9 m/s, suggesting the raptor cannot catch the person. However, participants note that the frequency change indicates the raptor is moving toward the person, raising questions about the accuracy of the initial assumptions and calculations. Overall, the conversation highlights the complexities of applying physics to hypothetical scenarios for entertainment.
winowmak3r
Messages
24
Reaction score
0

Homework Statement



I like to visit reddit. Browsing I found this comic:
ueCsl.png

I'm assuming sea level.

Speed of sound: 340.29m/s


Homework Equations



Wavelength = velocity of wave / frequency

change in frequency = -(velocity source - velocity reciever) / wavelength
(SOURCE: http://en.wikipedia.org/wiki/Doppler_effect)

The Attempt at a Solution



My general method of solving this problem would be to find the wavelength of the raptor's war cry, then once I know that I can figure out how fast the raptor is traveling using the change in frequency formula.

I'm assuming the raptor's war cry is traveling at the speed of sound at sea level:

wavelength = (340.29m/s) / 1260Hz = .27007 m/cycle

Solving for the velocity of the source in the change in frequency equation I get:

-(change in frequency)*(wavelength)+(velocity of receiver) = (velocity of source)
-(60Hz)*.27007m/cycle+9m/s = 7.2m/s

The raptor has a lower velocity than the person, so the raptor will never catch up with him. However, a velocity of a human of 9m/s is Olympic sprinter speed, so am I correct to assume the person will still get eaten because a human can't keep that constant running velocity?

I realize the comic is probably just someone making stuff up without doing the math, so I'm wondering if my solution is correct. I'm pretty sure the math is sound, but without any confidence that the problem is realistic (like the problems I usually encounter) I have no idea if my solution is reasonable.

By the way, this is purely for entertainment purposes. I just enjoy solving stuff like this, it's a nice break from the really hard (and sometimes boring) stuff.
 
Physics news on Phys.org


I don't *think* that can be quite right. The fact that the frequency received is higher than the emitted frequency suggests that the velociraptor is moving towards the person. I'll have a look at the equations a bit later!
 


My thoughts exactly. However, I think the problem is that the difference in frequency observed from the emitted is simply not large enough. As the raptor moves towards the person, the frequency should get larger as the raptor increases in velocity, correct? As I've said before, I just don't think the numbers for the frequency observed is correct for something that is supposed to be moving faster than 9m/s.

I get a -7.2m/s as my final velocity, but I took the absolute value of it because I didn't really set an initial frames of reference or anything. Could it be, perhaps, that the raptor is moving at 9m/s + 7.2m/s, that the velocity I got is really how fast the raptor is approaching the person relative to the person's velocity? So the raptor is really going something like 16.2m/s. Now I'm not so confident I've got it right. Any insight would be appreciated!
 


The fact that the measured frequency is higher than the emitted frequency suggests that the dinosaur is gaining on the person. Its like running away from a police car; although the increase might not be as large, the frequency is still higher and the police car is definitely catching you up!
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Replies
3
Views
2K
Replies
13
Views
4K
Replies
18
Views
13K
Replies
1
Views
2K
Replies
1
Views
7K
Replies
3
Views
10K
Replies
6
Views
24K
Back
Top